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At this zenith sin 8 = 1.0. Solving for t. yields t, = tP+ (up)y/go = 1 + 375/32.2 = 12.6 sec The trajectory maximum height or zenith can be determined:

= 187.5 + 375(11.6) - ±32.2(11.6)2 = 2370 ft The range during ascent to the zenith point is

The time of flight for the descent is, using yz = \got2,

The final range or x distance to the impact point is found by knowing that the initial horizontal velocity at the zenith (uz)x is the same as the horizontal velocity at propulsion termination (up)x:

The total range for ascent and descent is 855 + 855 = 1710. The time to impact is 12.6 + 12.1 = —24.7 sec. The vertical component of the impact or final velocity Uf is uf = g0(tf - t,) = 32.2 x 12.1 = 389.6 ft/ sec

The impact angle Of can be found:

If drag had been included, it would have required an iterative solution for finite elements of the flight path and all velocities and distances would be somewhat lower in value. A set of flight trajectories for a sounding rocket is given in Ref. 4-5.

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Project Management Made Easy

Project Management Made Easy

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