At this zenith sin 8 = 1.0. Solving for t. yields t, = tP+ (up)y/go = 1 + 375/32.2 = 12.6 sec The trajectory maximum height or zenith can be determined:

= 187.5 + 375(11.6) - ±32.2(11.6)2 = 2370 ft The range during ascent to the zenith point is

The time of flight for the descent is, using yz = \got2,

The final range or x distance to the impact point is found by knowing that the initial horizontal velocity at the zenith (uz)x is the same as the horizontal velocity at propulsion termination (up)x:

The total range for ascent and descent is 855 + 855 = 1710. The time to impact is 12.6 + 12.1 = —24.7 sec. The vertical component of the impact or final velocity Uf is uf = g0(tf - t,) = 32.2 x 12.1 = 389.6 ft/ sec

The impact angle Of can be found:

If drag had been included, it would have required an iterative solution for finite elements of the flight path and all velocities and distances would be somewhat lower in value. A set of flight trajectories for a sounding rocket is given in Ref. 4-5.

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Project Management Made Easy

Project Management Made Easy

What you need to know about… Project Management Made Easy! Project management consists of more than just a large building project and can encompass small projects as well. No matter what the size of your project, you need to have some sort of project management. How you manage your project has everything to do with its outcome.

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