Bedford Astronomy Club
where the following denomination has been inserted for the sake of brevity:
Integrating Eq. 4.6.60 from R = R; at t = 0, we find
= R/Rl dyA/TTi = ln ca r / r11 + l/3\y2 + l) It follows from Eq. 4.6.62 that
R + ^
Was this article helpful?
Write For Us