C11 C22 C33 C3 C3 C12 C21 Cii2 12141 C11 C22 C33

But, since each element of C is equal to its cofactor in |C|,

Consequently,

1 - 2c22 - 2€j2 = C" + C" C" + C" Ca + C"2 = C„ (29)

To see that Eqs. (1) and (3) are satisfied if X and 8 are given by Eqs. (19) and (20), note that

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